So I've been doing algebra since the start of the school year. I have since then accepted the fact that, after getting many, many solutions like (x-y)(x^2+y^2) 2(n-2)(n-1)
------------------ and -------------
(x+y)^3 (n+2)^2
that I will never again have an actual integer as an answer to the problem I'm working on.
But today, I had a problem starting like this:
3d^2-9d+6 6-2d
---------------- * --------
2d^2-10d+12 3-3d
Eventually I ended up with:
3(d-1) 2(3-d)
-------- * ---------
2(d-3) 3(1-d)
Mommy helped me from there. We figured out that the solution to the problem was 1.*
1.
1.
1!!!!!!!!!!!!!!!!!!!!!!
I got a number, I got a number...<throws confetti>
*This is assuming that d does not equal 1, 2, or 3.
Yay!
ReplyDeletealgebra is awesome and so are YOU!
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